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«9-sinflar uchun test 4-chorak»
Tuzdi:____Muminova N.T.
Ekspert:___Ashuraliyeva S.S.
Matematika 9-sinf
4-chorak uchun test topshiriqlari
1-variant
1. an=n+3 qonuniyat bilan berilgan sonli ketma-ketlikning dastlabki uchta hadini toping
A) 4,5,6 B) 1,2,3 C) 7,5,4 D) 7,8,10
2. Arifmetik progressiyada
=3, d=-2.
S
ni toping?
A) -9797 B) -9798 C) 7979 D) 2009 E) 9697
3. Arifmetik progressiyada d=4, S
=5000 bo’lsa, a
ni toping?
A) -2 B) 2 C) 100 D) 1250 E) 5
4. Arifmetik progressiyada
=1,
=301 bo’lsa, d ni toping?
A) 4 B) 2 C) 3 D) 3,5 E) 5
5 Arifmetik progressiyada
=20 bo’lsa,
S
ni toping?
A) 90 B) 110 C) 200 D) 100 E) aniqlab bo’lmaydi.
6. Geometrik progressiyada
=2, q=3 bo’lsa, S
ni toping?
A) A) 335 B) 336 C) 337 D) 728 E) to’g’ri javob berilmagan
7. Geometrik progressiyada q=
, S=364 bo’lsa,
ni toping?
A)
B) 81 C)
D) 240 E) 243
8. Cheksiz kamayuvchi geometrik progressiyada
, S=16 bo’lsa, q ni toping?
A)
B)
C)
D)
E)
9. Geometrik progressiyada
,
bo’lsa, S ni toping?
A)
B) 3 C)
D) 2 E)
10. Aylananing berilgan nuqtasidan radiusga teng bo’lgan ikkita vatar o’tkazilgan. Ular orasidagi burchakni toping
A) 1200 B) 1400 C) 1300 D) 1500
11. ABCD parallelogramning A o’tkir burchagining bissektrisasi uning BC tomonini E nuqtada kesib o’tadi Agar AB=9 , AD=15 bo’lsa EC ni toping.
J:_______________________
12. Rombning tomonlaridan biri bilan uning diognallari hosil qilgan burchaklarni nisbati 3:6 bo’lsa romb burchaklarini toping J:____________________________
13. 4 va 9 sonlari orasiga bitta musbat shunday sonni qo`yinki, natijada geometrik progressiyaning kema-ket uchta hadi hosil bo`lsin.J:___________________
14. Teng yonli trapetsiyaning katta asosi 2,7 m yon tomoni 1 m ga ular orasidagi burchak 600ga teng. Trapetsiya ning kichik asosini toping J:______________________
15.
bo`lsa,
ni toping.
J:______________________